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40a^2-70a=0
a = 40; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·40·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*40}=\frac{0}{80} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*40}=\frac{140}{80} =1+3/4 $
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